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Target
Solute carrier organic anion transporter family member 2A1
Ligand
BDBM35847
Substrate
n/a
Ki
>10000±n/a nM
Comments
PDSP_1462
Citation
Abramovitz, M; Adam, M; Boie, Y; Carrière, M; Denis, D; Godbout, C; Lamontagne, S; Rochette, C; Sawyer, N; Tremblay, NM; Belley, M; Gallant, M; Dufresne, C; Gareau, Y; Ruel, R; Juteau, H; Labelle, M; Ouimet, N; Metters, KM The utilization of recombinant prostanoid receptors to determine the affinities and selectivities of prostaglandins and related analogs. Biochim Biophys Acta 1483:285-93 (2000) [PubMed] Article
More Info.:
Target
Name:
Solute carrier organic anion transporter family member 2A1
Synonyms:
OATP2A1 | Prostaglandin Transporter | SLC21A2 | SLCO2A1 | SO2A1_HUMAN
Type:
Enzyme Catalytic Domain
Mol. Mass.:
70068.67
Organism:
Homo sapiens (Human)
Description:
Prostaglandin Transporter 0 HUMAN::Q92959
Residue:
643
Sequence:
MGLLPKLGASQGSDTSTSRAGRCARSVFGNIKVFVLCQGLLQLCQLLYSAYFKSSLTTIEKRFGLSSSSSGLISSLNEISNAILIIFVSYFGSRVHRPRLIGIGGLFLAAGAFILTLPHFLSEPYQYTLASTGNNSRLQAELCQKHWQDLPPSKCHSTTQNPQKETSSMWGLMVVAQLLAGIGTVPIQPFGISYVDDFSEPSNSPLYISILFAISVFGPAFGYLLGSVMLQIFVDYGRVNTAAVNLVPGDPRWIGAWWLGLLISSALLVLTSFPFFFFPRAMPIGAKRAPATADEARKLEEAKSRGSLVDFIKRFPCIFLRLLMNSLFVLVVLAQCTFSSVIAGLSTFLNKFLEKQYGTSAAYANFLIGAVNLPAAALGMLFGGILMKRFVFSLQAIPRIATTIITISMILCVPLFFMGCSTPTVAEVYPPSTSSSIHPQSPACRRDCSCPDSIFHPVCGDNGIEYLSPCHAGCSNINMSSATSKQLIYLNCSCVTGGSASAKTGSCPVPCAHFLLPAIFLISFVSLIACISHNPLYMMVLRVVNQEEKSFAIGVQFLLMRLLAWLPSPALYGLTIDHSCIRWNSLCLGRRGACAYYDNDALRDRYLGLQMGYKALGMLLLCFISWRVKKNKEYNVQKAAGLI
Inhibitor
Name:
BDBM35847
Synonyms:
(15S)-prostaglandin E2 | (5Z,11alpha,13E,15S)-11,15-dihydroxy-9-oxoprosta-5,13-dien-1-oic acid | (5Z,13E,15S)-11alpha,15-dihydroxy-9-oxoprosta-5,13-dien-1-oic acid | (E,Z)-(1R,2R,3R)-7-(3-Hydroxy-2-((3S)-(3-hydroxy-1-octenyl))-5-oxocyclopentyl)-5-heptenoic acid | CHEMBL548 | DINOPROSTONE | PGE2 | [3H]Dinoprostone | [3H]PGE2 | [3H]Prostaglandin E2 | prostaglandin E2
Type:
radiolabeled ligand
Emp. Form.:
C20H32O5
Mol. Mass.:
352.4651
SMILES:
CCCCC[C@H](O)\C=C\[C@H]1[C@H](O)CC(=O)[C@@H]1C\C=C/CCCC(O)=O